C++實(shí)現(xiàn)將一個(gè)字符串中的字符替換成另一個(gè)字符串的方法
本文實(shí)例講述了C++實(shí)現(xiàn)將一個(gè)字符串中的字符替換成另一個(gè)字符串的方法,分享給大家供大家參考。具體方法如下:
題目要求:
原地實(shí)現(xiàn)字符串中的每個(gè)空格替換成"%20",例如輸入"We are happy", 輸出"We%20are%20happy"
被替換的字符串當(dāng)然不僅僅是空格,上面只是個(gè)例子
這是道很好的題目,也是百度面試中的一道題,題目不難,但是問題得考慮全面。這里給出如下實(shí)現(xiàn)代碼:
#include <iostream>
#include <vector>
#include <cassert>
using namespace std;
int findNumberFirst(const char *str, const char *dest, vector<int>& pvec)
{
if (str == NULL || dest == NULL)
return 0;
int pos = 0;
int lenStr = strlen(str);
int lenDest = strlen(dest);
if (lenStr < lenDest)
return 0;
int count = 0;
while (pos <= lenStr - lenDest)
{
if (strncmp(str + pos, dest, strlen(dest)) == 0)
{
pvec.push_back(pos);
pos += lenDest;
count++;
}
else
{
pos++;
}
}
return count;
}
int findNumberLast(const char *str, const char *dest, vector<int> &pvec)
{
if (str == NULL || dest == NULL)
return 0;
int strLen = strlen(str);
int destLen = strlen(dest);
if (strLen < destLen)
return 0;
int pos = 0;
while (pos <= strLen - destLen)
{
if (strncmp(str + pos, dest, strlen(dest)) == 0)
{
pos += destLen;
pvec.push_back(pos - 1);
}
else
{
pos++;
}
}
return pvec.size();
}
void replaceArray(char *str, const char *src, const char *dest)
{
if (str == NULL || src == NULL || dest == NULL)
return;
vector<int> pvec;
int strLen = strlen(str);
int srcLen = strlen(src);
int destLen = strlen(dest);
if (strLen < srcLen)
return;
int posBefore = 0;
int posAfter = 0;
if (srcLen < destLen)
{
int count = findNumberLast(str, src, pvec);
if (count <= 0)
return;
posAfter = strLen + count * (destLen - srcLen) - 1;
posBefore = strLen - 1;
while (count > 0 && posBefore >= 0)
{
if (pvec[count - 1] == posBefore)
{
posAfter -= destLen;
strncpy(str + posAfter + 1, dest, strlen(dest));
count--;
posBefore--;
}
else
{
str[posAfter--] = str[posBefore--];
}
}
}
else if (strLen > destLen)
{
int count = findNumberFirst(str, src, pvec);
if (count <= 0)
return;
posAfter = 0;
posBefore = 0;
int i = 0;
while (count >= 0 && posBefore < strLen)
{
if (count > 0 && pvec[i] == posBefore)
{
strncpy(str + posAfter, dest, strlen(dest));
posAfter += destLen;
count--;
posBefore += srcLen;
i++;
}
else
{
str[posAfter++] = str[posBefore++];
}
}
str[posAfter] = '\0';
}
}
void main()
{
char *str = new char[100];
if (str == NULL)
return;
memset(str, '\0', 100);
const char *src = " ";
const char *dest = "%20";
//case1: 只有1個(gè)空格
strcpy(str, " ");
replaceArray(str, src, dest);
cout << "str: " << str << endl;
replaceArray(str, dest, src);
cout << "str: " << str << endl;
//case2: 兩個(gè)空格
strcpy(str, " ");
replaceArray(str, src, dest);
cout << "str: " << str << endl;
replaceArray(str, dest, src);
cout << "str: " << str << endl;
//case3: 正常情況
strcpy(str, "we are happy");
replaceArray(str, src, dest);
cout << "str: " << str << endl;
replaceArray(str, dest, src);
cout << "str: " << str << endl;
//case3: 空格在前
strcpy(str, " we are happy");
replaceArray(str, src, dest);
cout << "str: " << str << endl;
replaceArray(str, dest, src);
cout << "str: " << str << endl;
//case4: 空格在后
strcpy(str, "we are happy ");
replaceArray(str, src, dest);
cout << "str: " << str << endl;
replaceArray(str, dest, src);
cout << "str: " << str << endl;
//case4: 沒空格
strcpy(str, "wearehappy");
replaceArray(str, src, dest);
cout << "str: " << str << endl;
replaceArray(str, dest, src);
cout << "str: " << str << endl;
//case5: 兩邊一樣
strcpy(str, "we are happy");
replaceArray(str, src, dest);
cout << "str: " << str << endl;
src = "%20";
assert(dest == "%20");
replaceArray(str, dest, src);
cout << "str: " << str << endl;
}
分析上述代碼,很有意思的一個(gè)情況是srcLen和destLen或大或小的情形,其邊界條件的判定不一樣。比如we are happy為例子,從后往前拷貝時(shí),count=2。
在count=0時(shí),恰好將最前面的空格替換完成,we則不用重復(fù)拷貝。但是對(duì)于從前往后拷貝,當(dāng)count=0時(shí),最后面的happy將不會(huì)被拷貝。
希望本文所述實(shí)例對(duì)大家C++程序算法設(shè)計(jì)的學(xué)習(xí)有所幫助。
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