python?time模塊計(jì)算時(shí)間之間的差距(練習(xí)題)

更新時(shí)間：2023年05月15日 10:26:01 作者：Hy海洋

這篇文章主要介紹了python?time模塊計(jì)算時(shí)間之間的差距,本文通過(guò)實(shí)例代碼給大家介紹的非常詳細(xì)，對(duì)大家的學(xué)習(xí)或工作具有一定的參考借鑒價(jià)值，需要的朋友可以參考下

python time模塊計(jì)算時(shí)間之間的差距

練習(xí)題

1. 當(dāng)前月1號(hào)對(duì)應(yīng)的0點(diǎn)的時(shí)間戳

 # 定義一個(gè)當(dāng)前月分的一號(hào)0點(diǎn)字符串格式的時(shí)間
 now_time = time.strftime('%Y-%m-01 00:00:00')
 # 將格式化時(shí)間轉(zhuǎn)換為結(jié)構(gòu)化時(shí)間
 jiegou = time.strptime(now_time, '%Y-%m-%d %H:%M:%S')
 # 將結(jié)構(gòu)化時(shí)間轉(zhuǎn)換為對(duì)應(yīng)的時(shí)間戳
 shijiancuo = time.mktime(jiegou)
 print('%s對(duì)應(yīng)的時(shí)間戳為%s'%(now_time,shijiancuo))

2. n1的時(shí)間 n2的時(shí)間 n2 - n1的時(shí)間經(jīng)歷里多少年月日時(shí) 分秒

思想：需要首先將兩個(gè)字符串時(shí)間轉(zhuǎn)換為時(shí)間戳格式，然后相減，再轉(zhuǎn)換為結(jié)構(gòu)化時(shí)間，然后減去時(shí)間戳最開(kāi)始時(shí)間(倫敦時(shí)間:1970/01/01 00:00:00)

 import time
 n1 = '2019-07-18 20:07:56'
 n2 = '2019-07-19 22:03:12'
 # 格式化時(shí)間轉(zhuǎn)換為結(jié)構(gòu)化時(shí)間
 struct_time1, struct_time2 = time.strptime(n1, '%Y-%m-%d %H:%M:%S'), time.strptime(n2, '%Y-%m-%d %H:%M:%S')
 # 結(jié)構(gòu)化時(shí)間轉(zhuǎn)換為時(shí)間戳格式
 struct_time1, struct_time2 = time.mktime(struct_time1), time.mktime(struct_time2)
 # 差的時(shí)間戳
 diff_time = struct_time2 - struct_time1
 # 將計(jì)算出來(lái)的時(shí)間戳轉(zhuǎn)換為結(jié)構(gòu)化時(shí)間
 struct_time = time.gmtime(diff_time)
 # 減去時(shí)間戳最開(kāi)始的時(shí)間 并格式化輸出
 print('過(guò)去了{(lán)0}年{1}月{2}日{(diào)3}小時(shí){4}分鐘{5}秒'.format(
     struct_time.tm_year-1970,
     struct_time.tm_mon-1,
     struct_time.tm_mday-1,
     struct_time.tm_hour,
     struct_time.tm_min,
     struct_time.tm_sec
 ))

補(bǔ)充：python-time模塊計(jì)算時(shí)間差

import time
# t = time.time()
# print(t)
# z = time.strftime('%Y-%m-%d %H:%M:%S')
# print(z)
#
# a = time.localtime(time.time())
# print(a)
nowtime = time.time()
longtime = time.strptime('2018-10-17 6:0:0','%Y-%m-%d %H:%M:%S')
print(longtime)
d = time.mktime(longtime)
print(d)
new = nowtime - d
print(new)
s = time.localtime(new)
ss = time.strftime('%H:%M:%S',time.localtime(new))
print(ss)

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