如何實(shí)現(xiàn)SQL的等價物IN和NOT IN?
我有一個包含所需值的列表。下面是一個場景：
df = pd.DataFrame({'countries':['US','UK','Germany','China']})
countries = ['UK','China']
 
# pseudo-code:
df[df['countries'] not in countries]

df = pd.DataFrame({'countries':['US','UK','Germany','China']})
countries = pd.DataFrame({'countries':['UK','China'], 'matched':True})
 
# IN
df.merge(countries,how='inner',on='countries')
 
# NOT IN
not_in = df.merge(countries,how='left',on='countries')
not_in = not_in[pd.isnull(not_in['matched'])]

# IN
something.isin(somewhere)
 
# NOT IN
~something.isin(somewhere)

>>> df
  countries
0        US
1        UK
2   Germany
3     China
>>> countries
['UK', 'China']
>>> df.countries.isin(countries)
0    False
1     True
2    False
3     True
Name: countries, dtype: bool
>>> df[df.countries.isin(countries)]
  countries
1        UK
3     China
>>> df[~df.countries.isin(countries)]
  countries
0        US
2   Germany

import pandas as pd
columns = ['name','country']
index = [1,2,3,4]
row1 = ['a','China']
row2 = ['b','UK']
row3 = ['c','USA']
row4 = ['d','HK']

df = pd.DataFrame([row1,row2,row3,row4],
                   index=index,
                   columns=columns)
df

chinese = ['China','HK']

df[df.country.isin(chinese)]