C++ Primer Plus詳解
1.各種數(shù)據(jù)類(lèi)型的長(zhǎng)度
int main(void)
{
using namespace std;
int n(3); // C++還可以這么賦值
int m{6};
int f = {8};
int n_int = INT_MAX; //聲明變量同時(shí)賦值=初始化
short n_short = SHRT_MAX;
long n_long = LONG_MAX;
long long n_llong = LLONG_MAX;
cout << "n = " << n << endl;
cout << "m = " << m << endl;
cout << "f = " << f << endl;
cout << "int is " << sizeof(int) << " bytes." << endl; // sizeof是運(yùn)算符不是clmits中的函數(shù).INT_MAX是
cout << "short is " << sizeof n_short << " bytes." << endl; //函數(shù)必須帶括號(hào),sizeof(運(yùn)算符)在這里可以不跟括號(hào),但查看數(shù)據(jù)類(lèi)型必須加括號(hào)
cout << "long is " << sizeof n_long << " bytes." << endl;
cout << "long long is " << sizeof n_llong << " bytes." << endl;
cout << "Maximum values: " << endl;
cout << "int: " << n_int << endl;
cout << "short: " << n_short << endl;
cout << "long: " << n_long << endl;
cout << "long long: " << n_llong << endl;
return 0;
}
2. 無(wú)符號(hào)數(shù)據(jù)類(lèi)型及cout進(jìn)制顯示
2.1 無(wú)符號(hào)數(shù)據(jù)類(lèi)型及溢出
#include <iostream>
#include <climits> //可以查看數(shù)據(jù)類(lèi)型最大值最小值
int main(void)
{
using namespace std;
short sam = SHRT_MAX; //-32768-32767 (16位) longlong > long(至少32位)> int > short(至少16位)
unsigned short sue = sam; // 0-65535
cout << "sam has " << sam << " dolloars and sue has " << sue << " dolloars" << endl;
cout << "Add 1 dolloars to each account" << endl;
sam = sam + 1;
sue = sue + 1;
cout << "Now sam has " << sam << " dolloars and sue has " << sue << " dolloars" << endl;
sam = 0;
sue = 0;
sam = sam - 1;
sue = sue - 1;
cout << "Now sam has " << sam << " dolloars and sue has " << sue << " dolloars" << endl;
return 0;
}
2.2 cout十六進(jìn)制顯示
#include <iostream>
int main(void)
{
using namespace std;
int cheat = 42; //十進(jìn)制
int waist = 0x42; //十六進(jìn)制
int inseam = 042; //八進(jìn)制
cout << hex; //修改cout顯示整數(shù)的方式
cout << "cheat = " << cheat << " 42 (in decimal)" << endl;
cout << "waist = " << waist << " 0x42 (in hexadicimal)" << endl;
cout << "inseam = " << inseam << " 042 (in octal)" << endl; // cout默認(rèn)以十進(jìn)制顯示整數(shù)
return 0;
}
2.3 cout 八進(jìn)制十進(jìn)制十六進(jìn)制顯示
#include <iostream>
int main(void)
{
using namespace std;
int cheat = 42;
int waist = 0x42;
int inseam = 042;
cout << "cheat = " << cheat << " 42 (in decimal)" << endl; // cout默認(rèn)十進(jìn)制顯示
cout << hex; //修改cout為十六進(jìn)制顯示
cout << "waist = " << waist << " 0x42 (in hexadicimal)" << endl;
cout << oct; //修改cout為八進(jìn)制顯示
cout << "inseam = " << inseam << " 042 (in octal)" << endl;
return 0;
}
3.char、ASCII、\n
3.1 char類(lèi)型
#include <iostream>
int main(void)
{
using namespace std;
char ch;
cout << "Enter a character:" << endl;
cin >> ch; //cin將鍵盤(pán)輸入的M轉(zhuǎn)換為77
cout << "Hello, thanks you for the " << ch << " character." << endl; //cout將77轉(zhuǎn)換為M,cin和cout的行為由變量類(lèi)型引導(dǎo)
return 0;
}
3.2 ASCII與char、cout.put()
#include <iostream>
int main()
{
using namespace std;
char ch = 'M';
int i = ch;
cout << "The ASCII code for " << ch << " is " << i << endl;
cout << "Add one to the character code:" << endl;
ch = ch + 1; //顯示下一個(gè)字符
i = ch;
cout << "The ASCII code for " << ch << " is " << i << endl;
cout << "Displaying char ch using cout.put(ch)" << endl; // iostream類(lèi)(數(shù)據(jù)以及操作數(shù)據(jù)的方法)的對(duì)象cin、cout 矩形(對(duì)象)平移(方法)
cout.put(ch); //用對(duì)象訪問(wèn)類(lèi)里面的操作方法(函數(shù))、
cout.put('!');
cout.put('A');
cout << "Done" << endl;
return 0;
}cin與cout的行為由變量引導(dǎo)


3.3 轉(zhuǎn)義字符換行
#include <iostream>
int main(void)
{
using namespace std;
int n = 10;
cout << "Hello world!" << endl;
cout << "Good morning!\n";//使用轉(zhuǎn)義字符換行,顯示字符串這種方法簡(jiǎn)單一點(diǎn),\n是一個(gè)字符哦(換行符)
cout << "What's your name?" << '\n';
cout << "What's your name?" << "\n";
cout << "n = " << n << endl;
cout << "n = " << n << "\n";
return 0;
}
4.const
#include <iostream>
int main()
{
using namespace std;
const int toes = 10; //必須在聲明時(shí)賦值(之后不準(zhǔn)修改)(對(duì)const初始化)
/*const int toes;
toes = 10;這種是錯(cuò)誤的*/
return 0;
}5.浮點(diǎn)數(shù)(整數(shù)部分+小數(shù)部分)
#include <iostream>
int main()
{
using namespace std;
cout.setf(ios_base::fixed, ios_base::floatfield);
float tub = 10.0 / 3.0;
const float million = 1.0E6;
cout << "tub = " << tub << endl; // cout默認(rèn)輸出小數(shù)點(diǎn)后六位
cout << "A million tubs = " << million * tub << endl; // float精度達(dá)不到
cout << "Ten million tubs = " << 10 * million * tub << endl; // float精度達(dá)不到
double mint = 10.0 / 3.0;
cout << "A million mint = " << million * mint << endl;
cout << "Ten million mint = " << 10 * million * mint << endl; // double精度比f(wàn)loat高
return 0;
}
6. 比較大的浮點(diǎn)數(shù)
#include <iostream>
int main()
{
using namespace std;
float a = 2.34E22; // 2.34e/E+22 2.34*10^22
float b = a + 1.0;
cout << "a = " << a << endl;
cout << "b = " << b << endl; //a = b
cout << "b - a = " << b - a << endl; // float位數(shù)只有前六位或前七位有效
return 0;
}
7.float與double的精度
float單精度 至少32位 double雙精度 至少48位
浮點(diǎn)數(shù)在內(nèi)存中如何存儲(chǔ)的? int 類(lèi)型 5 以0101二進(jìn)制存儲(chǔ)這個(gè)好理解
float 8.25 單精度 內(nèi)存中32位(bit) double 64位 計(jì)算機(jī)存浮點(diǎn)數(shù)都是以科學(xué)計(jì)數(shù)法的方式存儲(chǔ)的 IEEE標(biāo)準(zhǔn)
8.25 科學(xué)計(jì)數(shù)法 8.25 * 10^0 112.5 科學(xué)計(jì)數(shù)法 1.125 * 10^2 十進(jìn)制的科學(xué)計(jì)數(shù)法 但是計(jì)算機(jī)只認(rèn)識(shí)二進(jìn)制的科學(xué)計(jì)數(shù)法
8.25 二進(jìn)制的科學(xué)計(jì)數(shù)法(分成整數(shù)部分(倒序)+小數(shù)部分(正序)) 1000.01 轉(zhuǎn)換為科學(xué)計(jì)數(shù)法 為1.00001*2^3
50.25 整數(shù)部分(32+16+2) 110010.01 任何一個(gè)浮點(diǎn)數(shù)二進(jìn)制科學(xué)計(jì)數(shù)法為 1.?????*2^x 整數(shù)部分一定為1
符號(hào)占1bit 正數(shù)為 0,負(fù)數(shù)為 1; 1.00001*2^3 指數(shù)3表示小數(shù)點(diǎn)右移
0 - 255 中間127 0-126(負(fù)次冪) 127-255(代表正次冪)
8.25在內(nèi)存中的表示: 符號(hào)位0 8位指數(shù)位 為127+3=130(3次冪) 130 -- 10000010 0(符號(hào)位) 10000010(指數(shù)位) 00001(小數(shù)位,23位) 000000000000000000(18個(gè)0)
整數(shù)部分1位,小數(shù)部分23位,共24位(二進(jìn)制) 4位對(duì)應(yīng)一個(gè)十進(jìn)制的數(shù) 24/4=6 對(duì)應(yīng)十進(jìn)制有效位6位 二進(jìn)制32位 課本56頁(yè)
double類(lèi)型: 十進(jìn)制13(52/4)位有效位 二進(jìn)制64位 符號(hào)位1 指數(shù)位11 小數(shù)位 52
11.17 二進(jìn)制 1011.001010111100001........(小數(shù)部分很難取整,無(wú)限長(zhǎng) ) 而float最多表示32位小數(shù)部分, 二進(jìn)制超過(guò)32位就不對(duì)了,十進(jìn)制超過(guò)6位就不對(duì)了
26.0在內(nèi)存中如何存儲(chǔ)的? 0100000110100000............
11010.00000000............
1.10100.......0 * 2 ^ 4
符號(hào)位:0 指數(shù)位:127 + 4 = 131 二進(jìn)制:10000011 小數(shù)位:010000000000...........
0.75 二進(jìn)制 0.110000.............
1.10*(2^-1)
符號(hào)位:0 指數(shù)位:127 + (-1) = 126 二進(jìn)制:01111110 小數(shù)位:1000000000...........
-2.5 二進(jìn)制 10.1
-1.01*2^1
符號(hào)位:1 指數(shù)位:127 + 1 = 128 二進(jìn)制:10000000 小數(shù)位:0100000000...........
8.float的誤差
/*
* @Description:
* @Date: 2022-02-14 13:25:40
* @LastEditTime: 2022-02-14 13:56:58
* @FilePath: \C++\第三章\class6\6_1.cpp
*/
// 26.0在內(nèi)存中如何存儲(chǔ)的? 11010.00000000............ 1.10100.......0 * 2 ^ 4 符號(hào)位:0 指數(shù)位:127 + 4 = 131 二進(jìn)制:10000011 小數(shù)位:010000000000...........
#include <iostream>
int main(void)
{
using namespace std;
float hats, heads;
cout.setf(ios_base::fixed, ios_base::floatfield); //可以強(qiáng)制打印小數(shù)點(diǎn)后六位(沒(méi)辦法四舍五入),去掉這一句就可以四舍五入,輸出61.42000000.......0可以不顯示
cout << "Enter a number: "; // 50.25
cin >> hats;
cout << "Enter another number: "; // 11.17
cin >> heads;
cout << "hats = " << hats << " heads = " << heads << endl;
cout << "hats + heads = " << hats + heads << endl; // 61.42 的小數(shù)部分 0.42 二進(jìn)制01101...........無(wú)限,但是float二進(jìn)制小數(shù)部分只有23位有效,十進(jìn)制六位61.4199(近似有效)
cout << "hats - heads = " << hats - heads << endl;
cout << "hats * heads = " << hats * heads << endl;
cout << "hats / heads = " << hats / heads << endl; // folat精度不夠,二進(jìn)制只能顯示小數(shù)點(diǎn)后23位,所以不準(zhǔn),去掉setf()可四舍五入
return 0;
}
注視掉 cout.setf()

解決辦法:用double 可顯示二進(jìn)制小數(shù)點(diǎn)后53位,十進(jìn)制13位,我們用setf()顯示6位顯然也是準(zhǔn)確的

9.乘除法
#include <iostream>
int main(void)
{
using namespace std;
cout.setf(ios_base::fixed, ios_base::floatfield); //顯示小數(shù)點(diǎn)后六位
cout << "Integer division : 9/5 = " << 9 / 5 << endl; //整數(shù)相除結(jié)果取出整數(shù)部分
cout << "Float division : 9.0/5.0 = " << 9.0 / 5.0 << endl;
cout << "Mixed division : 9.0/5 = " << 9.0 / 5 << endl; //混合類(lèi)型
cout << "Mixed division : 9/5.0 = " << 9 / 5.0 << endl; //混合類(lèi)型 浮點(diǎn)型精度高于整型,提升精度為浮點(diǎn)型
cout << "Double division : 1e7 / 9.0 = " << 1e7 / 9.0 << endl; //都當(dāng)成double類(lèi)型來(lái)處理(精度高) 一般定義浮點(diǎn)數(shù)用double,編譯器默認(rèn)當(dāng)成double處理,除非你強(qiáng)制float
cout << "FLoat constance division : 1e7f / 9.0f = " << 1e7f / 9.0f << endl; //都當(dāng)成float類(lèi)型來(lái)處理
return 0;
}
10.求模運(yùn)算符
#include <iostream>
int main(void)
{
using namespace std;
const int pounds_per_stone = 14; //聲明整型類(lèi)型常量 14榜(pounds)=1英石(stone)
cout << "Enter your weight in pounds: ";
int lbs;
cin >> lbs;
int stone = lbs / pounds_per_stone;
int pounds = lbs % pounds_per_stone;
cout << lbs << "pounds = " << stone << " stone, " << pounds << " pounds." << endl;
return 0;
}
11.數(shù)值轉(zhuǎn)換
#include <iostream>
int main(void)
{
using namespace std;
cout.setf(ios_base::fixed, ios_base::floatfield);
float tree = 3;
int guess(3.9832); // C++特有賦值方式,這里取出小數(shù)的整數(shù)部分
int debt = 6.2E22; //超過(guò)了整型的取值范圍,結(jié)果不確定,對(duì)于int(32位 -2^31---2^31-1)太大了
cout << "tree = " << tree << endl;
cout << "guess = " << guess << endl;
cout << "debt = " << debt << endl;
return 0;
}
12.強(qiáng)制類(lèi)型轉(zhuǎn)換
#include <iostream>
int main(void)
{
using namespace std;
int auks, bats, coots;
auks = 19.99 + 11.99; //計(jì)算機(jī)用double類(lèi)型相加計(jì)算再轉(zhuǎn)換為整型,結(jié)果取整=31
bats = (int)19.99 + (int)11.99; // C語(yǔ)言格式
coots = int(19.99) + int(11.99); // C++語(yǔ)言格式
cout << "auks = " << auks << endl;
cout << "bats = " << auks << endl;
cout << "coots = " << auks << endl;
char ch = 'Z';
cout << "The code for " << ch << " is " << int(ch) << endl;
cout << static_cast<int>(ch) << endl; //強(qiáng)制類(lèi)型轉(zhuǎn)換
return 0;
}
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