Python 之 Json序列化嵌套類方式

更新時(shí)間：2020年02月27日 16:31:52 作者：IT-藍(lán)月

今天小編就為大家分享一篇Python 之 Json序列化嵌套類方式，具有很好的參考價(jià)值，希望對(duì)大家有所幫助。一起跟隨小編過來(lái)看看吧

想要用python自已手動(dòng)序列化嵌套類，就要明白兩個(gè)問題：

1.Json是什么？

2.Json支持什么類型？

答案顯而易見

Json就是嵌套對(duì)象

Json在python中支持列表，字典（當(dāng)然也支持int,string.....,不過說(shuō)這個(gè)也沒多大必要）

很好，等等，列表，字典？我們?cè)趐ython中學(xué)過列表，字典，字典列表，列表字典，字典字典，那，我們可不可以把類對(duì)象轉(zhuǎn)化為這些呢？

我可以很確定的告訴你，可以，并且，嵌套類都可以?。?！

下面就來(lái)實(shí)戰(zhàn)：

from flask import Flask
import json
 
app = Flask(__name__)
 
class City():
  def __init__(self,country,provider):
    self.country = country
    self.provider = provider
 
 
class School():
  def __init__(self,country,provider,name,nums):
    self.city = City(country,provider)
    self.name = name
    self.nums = nums
 
 
@app.route('/method0')
def method0():
  school = School('china','shanxi','wutaizhongxue','2000')
 
  s_temp0 = [school.city.country,school.city.provider,school.name,school.nums]
  return json.dumps(s_temp0)
 
 
@app.route('/method1')
def method1():
  school = School('china','shanxi','wutaizhongxue','2000')
 
  s_temp1 = {'country':school.city.country,'provider':school.city.provider,'name':school.name,'nums':school.nums}
  return json.dumps(s_temp1)
 
 
@app.route('/method2')
def method2():
  school = School('china','shanxi','wutaizhongxue','2000')
 
  s_temp2 = [{'country':school.city.country,'provider':school.city.provider},school.name,school.nums]
  return json.dumps(s_temp2)
 
 
@app.route('/method3')
def method3():
  school = School('china','shanxi','wutaizhongxue','2000')
 
  s_temp3 = {'city':[school.city.country,school.city.provider],'name':school.name,'nums':school.nums}
  return json.dumps(s_temp3)
 
 
@app.route('/method4')
def method4():
  school = School('china','shanxi','wutaizhongxue','2000')
 
  s_temp4 = {'city':{'country':school.city.country,'provider':school.city.provider},'name':school.name,'nums':school.nums}
  return json.dumps(s_temp4)
 
 
if __name__ == '__main__':
  app.run(debug=True)

執(zhí)行效果：