C語(yǔ)言編寫(xiě)五子棋游戲

更新時(shí)間：2020年02月06日 08:32:49 作者：weixin_46265516

這篇文章主要為大家詳細(xì)介紹了C語(yǔ)言編寫(xiě)五子棋游戲，文中示例代碼介紹的非常詳細(xì)，具有一定的參考價(jià)值，感興趣的小伙伴們可以參考一下

本文實(shí)例為大家分享了C語(yǔ)言編寫(xiě)五子棋游戲的具體代碼，供大家參考，具體內(nèi)容如下

一、構(gòu)建棋盤(pán)

首先可以用一個(gè)二維數(shù)組來(lái)構(gòu)建棋盤(pán)，下標(biāo)表示位置，內(nèi)容表示黑子白子或者空位。當(dāng)數(shù)組內(nèi)容為1時(shí)，該位置為白字，當(dāng)數(shù)組為0時(shí)，該位置為白子，空位輸出+

int w[11][11], flag = 0;
 int a, b;
 
 for (int k = 0; k < 11; k++)
   printf("第%d列\(zhòng)t", k);
  printf("\n");
  for (int i = 0; i < 11; i++) {
   for (int j = 0; j < 11; j++) {
    if (w[i][j] == 0) printf("黑\t");
    else if (w[i][j] == 1) printf("白\t");
    else printf("+\t");
   }
   printf("第%d行\(zhòng)n\n", i);
  }

二、判斷位置超范圍與錯(cuò)誤輸入

當(dāng)輸入的棋子坐標(biāo)超出范圍或者該位置已經(jīng)存在棋子，則再次輸入棋子坐標(biāo)。其中flag作為標(biāo)志作為判別黑手白手的標(biāo)志。

if (flag == 0) {
   printf("黑色下棋\n");
   scanf("%d %d", &a, &b);
   while (a < 0 || a>10 || b < 0 || b>10) {
    printf("此位置超出范圍，請(qǐng)重新輸入：");
    scanf("%d %d", &a, &b);
   }
   while (w[a][b] == 0 || w[a][b] == 1)   
   {
    printf("此位置已有棋子，請(qǐng)重新輸入：");
    scanf("%d %d", &a, &b);
   }
   flag = 1;
   w[a][b] = 0;
  }
  else {
   printf("白色下棋\n");
   scanf("%d %d", &a, &b);
   while (a < 0 || a>10 || b < 0 || b>10) {
    printf("此位置超出范圍，請(qǐng)重新輸入：");
    scanf("%d %d", &a, &b);
   }
   while (w[a][b] == 0 || w[a][b] == 1)
   {
    printf("此位置已有棋子，請(qǐng)重新輸入：");
    scanf("%d %d", &a, &b);
   }

三、判斷勝負(fù)

在五子棋中，出現(xiàn)五個(gè)棋子排成一排或者一列或者斜排即可判為勝出。每當(dāng)落下一個(gè)棋子，對(duì)該棋子前后上下斜排五個(gè)棋子進(jìn)行判別，超過(guò)五個(gè)連續(xù)的一樣顏色的棋子則勝出。

int A = 1, B = 1, jieguo = 0, C = 1, D = 1;
  int x = 1, y = 1, m = 1, n = 1;
  if (w[a][b] == 1) {
   for (int i = 1; i < 5; i++) {
    if (w[a][b + i] == 1) A++;
    else break;    
   }
   for (int i = 1; i < 5; i++) {
    if (w[a][b - i] == 1) A++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a+i][b] == 1) C++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a - i][b] == 1) C++;
    else break;
   }
   if (A > 4 || C > 4) jieguo = 1;//白棋勝利標(biāo)志
   else {
    for (int i = 1; i < 5; i++) {
     if (w[a+i][b + i] == 1) x++;
     else break;
    }
    for (int i = 1; i < 5; i++) {
     if (w[a-i][b - i] == 1) x++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a + i][b-i] == 1) y++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a - i][b+i] == 1) y++;
     else break;
    }
    if (x > 4 || y > 4) jieguo = 1;
   }
  }
  if (w[a][b] == 0) {
   for (int i = 1; i < 5; i++) {
    if (w[a][b + i] == 0) B++;
    else break;
   }
   for (int i = 1; i < 5; i++) {
    if (w[a][b - i] == 0) B++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a + i][b] == 0) D++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a - i][b] == 0) D++;
    else break;
   }
   if (B > 4 || D > 4) jieguo = 2;//黑棋勝利標(biāo)志
   else {
    for (int i = 1; i < 5; i++) {
     if (w[a + i][b + i] == 0) m++;
     else break;
    }
    for (int i = 1; i < 5; i++) {
     if (w[a - i][b - i] == 0) m++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a + i][b - i] == 0) n++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a - i][b + i] == 0) n++;
     else break;
    }
    if (m > 4 || n > 4) jieguo = 2;
   }
  }

程序完成

四、演示結(jié)果

五、源代碼

int main() {
 int w[11][11], flag = 0;
 int a, b;
 while (1) {
  if (flag == 0) {
   printf("黑色下棋\n");
   scanf("%d %d", &a, &b);
   while (a < 0 || a>10 || b < 0 || b>10) {
    printf("此位置超出范圍，請(qǐng)重新輸入：");
    scanf("%d %d", &a, &b);
   }
   while (w[a][b] == 0 || w[a][b] == 1)   
   {
    printf("此位置已有棋子，請(qǐng)重新輸入：");
    scanf("%d %d", &a, &b);
   }
   flag = 1;
   w[a][b] = 0;
  }
  else {
   printf("白色下棋\n");
   scanf("%d %d", &a, &b);
   while (a < 0 || a>10 || b < 0 || b>10) {
    printf("此位置超出范圍，請(qǐng)重新輸入：");
    scanf("%d %d", &a, &b);
   }
   while (w[a][b] == 0 || w[a][b] == 1)
   {
    printf("此位置已有棋子，請(qǐng)重新輸入：");
    scanf("%d %d", &a, &b);
   }
   flag = 0;
   w[a][b] = 1;
  }
  
  int A = 1, B = 1, jieguo = 0, C = 1, D = 1;
  int x = 1, y = 1, m = 1, n = 1;
  if (w[a][b] == 1) {
   for (int i = 1; i < 5; i++) {
    if (w[a][b + i] == 1) A++;
    else break;    
   }
   for (int i = 1; i < 5; i++) {
    if (w[a][b - i] == 1) A++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a+i][b] == 1) C++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a - i][b] == 1) C++;
    else break;
   }
   if (A > 4 || C > 4) jieguo = 1;//白棋勝利標(biāo)志
   else {
    for (int i = 1; i < 5; i++) {
     if (w[a+i][b + i] == 1) x++;
     else break;
    }
    for (int i = 1; i < 5; i++) {
     if (w[a-i][b - i] == 1) x++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a + i][b-i] == 1) y++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a - i][b+i] == 1) y++;
     else break;
    }
    if (x > 4 || y > 4) jieguo = 1;
   }
  }
  if (w[a][b] == 0) {
   for (int i = 1; i < 5; i++) {
    if (w[a][b + i] == 0) B++;
    else break;
   }
   for (int i = 1; i < 5; i++) {
    if (w[a][b - i] == 0) B++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a + i][b] == 0) D++;
    else break;
   }
   for (int i = 1; i < 5; i++)
   {
    if (w[a - i][b] == 0) D++;
    else break;
   }
   if (B > 4 || D > 4) jieguo = 2;//黑棋勝利標(biāo)志
   else {
    for (int i = 1; i < 5; i++) {
     if (w[a + i][b + i] == 0) m++;
     else break;
    }
    for (int i = 1; i < 5; i++) {
     if (w[a - i][b - i] == 0) m++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a + i][b - i] == 0) n++;
     else break;
    }
    for (int i = 1; i < 5; i++)
    {
     if (w[a - i][b + i] == 0) n++;
     else break;
    }
    if (m > 4 || n > 4) jieguo = 2;
   }
  }
 
  for (int k = 0; k < 11; k++)
   printf("第%d列\(zhòng)t", k);
  printf("\n");
  for (int i = 0; i < 11; i++) {
   for (int j = 0; j < 11; j++) {
    if (w[i][j] == 0) printf("黑\t");
    else if (w[i][j] == 1) printf("白\t");
    else printf("+\t");
   }
   printf("第%d行\(zhòng)n\n", i);
  }
  if (jieguo == 1) {
   printf("白棋勝利");
   break;
  }
  if (jieguo == 2) {
   printf("黑棋勝利");
   break;
  }
 }
 return 0;
}

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